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4.5x^2+15x+12=0
a = 4.5; b = 15; c = +12;
Δ = b2-4ac
Δ = 152-4·4.5·12
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3}{2*4.5}=\frac{-18}{9} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3}{2*4.5}=\frac{-12}{9} =-1+1/3 $
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